Binary Search 二分搜索

二分搜索的要點:

  1. 確立邊界,這樣會導致我們是在閉區間或是非閉區間搜尋

    1. 左側的邊界,ex: 0 or 1?

    2. 右側的邊界,ex: len(nums) or len(nums) - 1

  2. 循環條件的終止,ex: while left <= right or while left < right

def binarySearch(nums: List[int], target: int) -> int:
    left = 0
    right = len(nums) - 1
    while left <= right:
        mid = left + (right - left) // 2
        if nums[mid] == target:
            return mid
        elif nums[mid] < target:
            left = mid + 1
        elif nums[mid] > target:
            right = mid - 1
    return -1

Find Left Bound

def findLeftBound(nums: List[int], target: int) -> int:
    left = 0
    right = len(nums)
    while left < right:
        mid = left + (right - left) // 2
        if nums[mid] == target:
            right = mid
        elif nums[mid] < target:
            left = mid + 1
        elif nums[mid] > target:
            right = mid
    return left
def findLeftBound(nums: List[int], target: int) -> int:
    left = 0
    right = len(nums) - 1
    while left <= right:
        mid = left + (right - left) // 2
        if nums[mid] == target:
            right = mid - 1
        elif nums[mid] < target:
            left = mid + 1
        elif nums[mid] > target:
            right = mid - 1
    if left >= len(nums) or nums[left] != target:
        return -1
    return left

Find Right Bound

def findRightBound(nums: List[int], target: int) -> int:
    left = 0
    right = len(nums)
    while left < right:
        mid = left + (right - left) // 2
        if nums[mid] == target:
            left = mid + 1
        elif nums[mid] < target:
            left = mid + 1
        elif nums[mid] > target:
            right = mid
    return right - 1
def findRightBound(nums: List[int], target: int) -> int:
    left = 0
    right = len(nums) - 1
    while left <= right:
        mid = left + (right - left) // 2
        if nums[mid] == target:
            left = mid + 1
        elif nums[mid] < target:
            left = mid + 1
        elif nums[mid] > target:
            right = mid - 1
    if right < 0 or nums[right] != target:
        return -1
    return right

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